Fridrich method (modified) (part 4)



5. Orientation of the last layer

Table 9: Algorithms of orientation of the last layer


Case

Figure

Algorithms



1

Fridrich modified, part 5, case 1

R'F'L'FRF'LF



2

Fridrich modified, part 5, case 2

FB'URU'R'U'R'U'RUF'B



3

Fridrich modified, part 5, case 3

RU2R2U' - R2 - U'R2U2R



4

Fridrich modified, part 5, case 4

RU2R'U' - RUR'U' - RU'R'



5

Fridrich modified, part 5, case 5

U2 - RUR'URU2R'



6

Fridrich modified, part 5, case 6

RU2R'U'RU'R'



7

Fridrich modified, part 5, case 7

R2DR'U2 - RD'R'U2 - R'



8

Fridrich modified, part 5, case 8

R'F'LFRF'L'F



6. Permutation of edges

At this point, we have to permute the edges, which means to change their position, but not their orientation. It is necessary to look at the number of edges well positioned (as an example, in Figure 9, the red and yellow edge is in the correct position.

Fridrich modified, part 6, example of well-positioned edge
Figura 9: Example of a well posisioned edge (the red and yellow one).

Move the top layer, to see how many well-positioned edges we can get. There are three cases:

6.1. 0 edges well positioned

How are the edges exchanged? There are two possibilities (in Table 10):

Table 10: Permutation of edges - 0 edges well positioned


Case

Figure

Description

Algorithm



1

Fridrich modified, part 6, 0 edges well positioned, case 1

Seen from above, the edges are exchanged forming a cross

M2U - M2U2 - M2U - M2



2

Fridrich modified, part 6, 0 edges well positioned, case 2

Seen from above, the edges are exchanged diagonally

RB'R'B - FR'F - B'R'BR - F2 - U



6.2. 1 edge well positioned:

Turn the upper layer (or the whole cube, to see what is happening more clearly), until the matched edge is opposite us. In this point, there are two possibilities (see Table 11):

Table 11: Permutation of edges - 1 edge well positioned


Case

Figure

Description

Algorithm



1

Fridrich modified, part 6, 1 edge well positioned, case 1

Seen from above, the edges must turn clockwise

R'U - R'U' - R'U' - R'U - RUR2



2

Fridrich modified, part 6, 1 edge well positioned, case 2

Seen from above, the edges must turn counterclockwise

R2U'R' - U'R - UR - UR - U'R



6.3. 2 edges well positioned:

In this case, there is only a possibility (Table 12):

Table 12: Permutation of edges - 2 edges well positioned


Case

Figure

Description

Algorithm



1

Fridrich modified, part 6, 2 edges well positioned

Seen from above, the correct edges must be on the right and on the left. To get that, turn the upper layer (or the whole cube, to see it better).


RB'R'B - FR'F - B'R'BR - F2